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&&& &为了解决用户可能碰到关于"6xxx-11xx+x+4分解因式"相关的问题，突袭网经过收集整理为用户提供相关的解决办法，请注意，解决办法仅供参考，不代表本网同意其意见,如有任何问题请与本网联系。"6xxx-11xx+x+4分解因式"相关的详细问题如下:RT,我想知道:6xxx-11xx+x+4分解因式===========突袭网收集的解决方案如下===========
解决方案1：6xxx-11xx+x+4=6xxx
-6xx-5xx+ 5x-4x
+4=6xx(x-1) - 5x(x-1) -4(x-1)=(x-1) (6xx -5x -4)=(x-1) (2x +1)(3x-4)
================可能对您有帮助================
答：6xxx-11xx+x+4 =6xxx -6xx-5xx+ 5x-4x +4 =6xx(x-1) - 5x(x-1) -4(x-1) =(x-1) (6xx -5x -4) =(x-1) (2x +1)(3x-4)===========================================问：X后面的数字表示它的指数,要过程,谢谢答：X15+X14+X13+X12+X11+X10+X9+X8+X7+X6+X5+X4+X3+X2+X+1 =（X15+X14）+（X13+X12）+（X11+X10）+（X9+X8）+（X7+X6）+（X5+X4）+(X3+X2)+(X+1) =x14(x+1)+x12(x+1)+x10(x+1)+x8(x+1)+x6(x+1)+x4(x+1)+x2(x+1)+(x+1) =(x+1)(x14+x12+x10+x8+x6+x4+...===========================================分解成(2x+1)(3x+4)十字相乘将二次项系数6拆成&& &&&&& 2,3系数拆成&&&am...===========================================6x³-11x²+x+4
=6x³-6x²-5x²+x+4
=6x³-6x²-5x²+5x-4x+4
=6x²(x-1)-5x(x-1)-4(x-1)
=(x-1)*(6x²-5x-4)
=(x-1)*(2x+1)(...===========================================6x^3-11x^2+x+4=6x^3-6x^2-5x^2+5x-4x+4=(x-1)*(6x^2-5x-4)===========================================6x^3-11x^2+x+4
=(6x³-6x²)-5x²+x+4
=6x²(x-1)-(5x²-x-4)
=6x²(x-1)-(5x+4)(x-1)
=(x-1)((6x²-5x-4)
=(x-1)(3x-4)(2x+1)===========================================6x^3-11x^2+x+4
=6x^3-6x^2-5x^2+5x-4x+4
=6x^2(x-1)-5x(x-1)-4(x-1)
=(x-1)(6x^2-5x-4)
=(x-1)(2x+1)(3x-4)===========================================1.X^3+6X^2+11X+6=(X^3+X^2)+(5X^2+5X)+(6X+6)=X^2(X+1)+5X(X+1)+6(X+1)=(X+1)(X^2+5X+6)=(X+1)(X+2)(X+3)2. 6x^4+5x^3+3x^2-3x-2=6x^4+5x^3+(x^2+2x^2)-3x-2=(6x...===========================================1.X^3+6X^2+11X+6
=(X^3+X^2)+(5X^2+5X)+(6X+6)
=X^2(X+1)+5X(X+1)+6(X+1)
=(X+1)(X^2+5X+6)
=(X+1)(X+2)(X+3)
2. 6x^4+5x^3+3x^2-3x-2
=6x^4+5x^3+(x^2+2x^...===========================================如果是针对考试题目的话,试根法不失为一种不错的方法:
第一题:试根为x=1(一般就±1,±2,±0.5);所以(x-1)是其一个因式,然后第一个式子:x^4+4^3-7x^2-22x+24;
然后做多项式...===========================================x^4+x^2+1
=(x^4+2x^2+1)- x^2
=(x^2+1)^2-x^2
=(x^2+x+1)(x^2-x+1)
x^3-6x^2+11x+6
=x^3-6x^2+9x+2x+6
=x(x^2-6x+9)+2(x+3)
=x(x-3)^2+2(x+3)
=(x+3)(x^2+3x+2)
=(x+3)(x+...===========================================第一题要在复数范围内分解才有答案的,可是这不在高考范围内,所以,题目很有可能是有问题的
第二题=(x+1)(x+2)(x+3)
第三题=(a+3c)(b+a)(c+2b)===========================================
12345678910若关于x的多项式3x^2-px+1中含有因式x-1,则p的值为?_百度作业帮
若关于x的多项式3x^2-px+1中含有因式x-1,则p的值为?
设为（x-1）(3x+a)=3x²+(a-3)x-a=3x²-px+1;-a=1;a=-1;a-3=-pp=3-a=4;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什么不明白可以追问,已知多项式x四次方+2（x三次方）-x+m能分解因式,且有因式x-1,求m的值_百度作业帮
已知多项式x四次方+2（x三次方）-x+m能分解因式,且有因式x-1,求m的值
有因式x-1,即x=1,是方程x^4+2x^3-x+m=0的一解1^4+2*1^3-1+m=01+2-1+m=0m=-2
能分解因式，且有因式x-1,则有当x-1=0时原式=0,即把X=1代入到原式中有:1+2-1+m=0m=-2
m=-2& 解答过程见图：
1, 当x=1时,x-1=0故当x=1时,.x的四次方+2乘以x的三次方-x+m=0将x=1代入得:1+2-1+m=0故m=-2关于因式分解的20道数学题,知道几道回答几道,明天下午要交.完了我给追加40分.1.x^2-5x-36 2.x^2-14x+24 3.x^2-2x-8 4.-a^2-3a-2 5.x^4+x^3+6x^2+5x+5 6.14(m+n)^2-11(m+n)-15 7.x^2-(m+8)x+7(m+1)8.x^(n+2)-5x^(n+1)+4x^n (n为正整数）9.x^4-21x^2-100 10.x^4-3x_百度作业帮
关于因式分解的20道数学题,知道几道回答几道,明天下午要交.完了我给追加40分.1.x^2-5x-36 2.x^2-14x+24 3.x^2-2x-8 4.-a^2-3a-2 5.x^4+x^3+6x^2+5x+5 6.14(m+n)^2-11(m+n)-15 7.x^2-(m+8)x+7(m+1)8.x^(n+2)-5x^(n+1)+4x^n (n为正整数）9.x^4-21x^2-100 10.x^4-3x^3-28x^2 11.(x+1)(x-4)-6 12.4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)13.x^2+10x+21 14.(x^2+x+1)(x^2+x+2)-12 15.4x^2-4ax+a^2-b^216.x^4-x^3+x^2+2 17.x^2-5x(y-1)-6(1-y)^2 18.4x^2+2x-9y^2-3y19.a^2+4b^2+c^4-4ab-2ac^2+4bc^2-1 20.5+7(a+1)-6(a+1)^21.x^5+x+1 2.2a^2b^2+2a^2c^2+2b^2c^2-a^4-b^4-c^43(x^2+3x)^2-2(x^2+3x)-8 4.(x-1)(x-2)(x-3)(x-4)-1205.4x^2-4x-y^2+4y-3 6.2x^2-5xy-3y^2+x+11y-67 c为正整数，且a分之b+a分之c+c分之a=3 求证a=b=c
1)x^2-5x-36=(x-9)(x+4)2)x^2-14x+24=(x-2)(x-12)3)x^2-2x-8 =(x-4)(x+2)4)-a^2-3a-2 =-(x+1)(x+2)5)x^4+x^3+6x^2+5x+5 =(x^4+5x^2)+(x^3+5x)+(x^2+5 )=(x^2+5 )(x^2+x+1)6)14(m+n)^2-11(m+n)-15 =[2(m+n)-3][7(m+n)+5]=(2m+2n-3)(7m+7n+5)7)x^2-(m+8)x+7(m+1)=(x-7)(x-m-1)8)x^(n+2)-5x^(n+1)+4x^n=x^n(x^2-5x+4)=x^n(x-1)(x-4)9)x^4-21x^2-100 =(x^2-25)(x^2+4)10)x^4-3x^3-28x^2 =x^2(x^2-3x-28)=x^2(x-7)(x+4)11)(x+1)(x-4)-6 =x^2-3x-10=(x+2)(x-5)12)4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)=4x^(n+2)+6x^(n-1)-9x^n-x^(n-2)=(4x^4-9x^2+6x-1)x^(n-2)=(4x^4-4x^2-5x^2+6x-1)x^(n-2)=[(x+1)(x-1)4x^2-(5x-1)(x-1)]x^(n-2)=(4x^3+4x^2-5x+1)(x-1)x^(n-2)=(4x^3-x+4x^2-4x+1)(x-1)x^(n-2)=[(x(2x+1)(2x-1)+(2x-1)^2](x-1)x^(n-2)=(2x^2+3x-1)(2x-1)(x-1)x^(n-2)13)x^2+10x+21 =(x+3)(x+7)14)令x^2+x=A原式=（A+1）（A+2）-12=A^2+3A-10=(A-2)(A+5)=(x^2+x-2)(x^2+x+5)15)4x^2-4ax+a^2-b^2=[2x-(a+b)][2x-(a-b)]=(2x-a-b)(2x-a+b)16)x^4-x^3+x^2+2 =(x^4+2x^2+1)-x^2+(1-x^3) =(x^2+1)^2-x^2+(1-x)(x^2+x+1)=(x^2+x+1)(x^2-x+1)+(1-x)(x^2+x+1)=(x^2+x+1)(x^2-2x+2)17)x^2-5x(y-1)-6(1-y)^2 =6(y-1)^2 -5x(y-1)+x^2=[2(y-1)-x][3(y-1)-x]=(2y-x-2)(3y-x-3)18)4x^2+2x-9y^2-3y=(4x^2-9y^2)+(2x-3y)=(2x+3y)(2x-3y)+(2x-3y)=(2x-3y)(2x+3y+1)19)a^2-4ab+4b^2-2ac^2+4bc^2+c^4-1=(a-2b)^2-2(a-2b)c^2+c^4-1=(a-2b-c^2)-1=(a-2b-c^2-1)(a-2b-c^2+1)20)5+7(a+1)-6(a+1)^2 =[2(a+1)+1][-3(a+1)+5]=(2a+3)(2-3a) 问题补充1）x^5+x+1 ＝x^5-x^2+x^2+x+1 =x^2(x^3-1)+(x^2+x+1) =(x-1)(x^2+x+1)x^2+(x^2+x+1) =(x^2+x+1)(x^3-x^2+1) 2)2a^2b^2+2a^2c^2+2b^2c^2-a^4-b^4-c^4=4a^2b^2-(a^4+b^4+c^4+2a^2b^2-2a^2c^2-2b^2c^2)=(2ab)^2-(a^2+b^2-c^2)^2=(2ab+a^2+b^2-c^2)(2ab-a^2-b^2+c^2)=[(a+b)^2-c^2][c^2-(a-b)^2]=(a+b-c)(a+b+c)(c+a-b)(c-a+b) 3）(x^2+3x)^2-2(x^2+3x)-8=[(x^2+3x)-4][(x^2+3x)+2]=(x^2+3x-4)(x^2+3x+2)4)(x-1)(x-4)(x-3)(x-2)-120=(x^2-5x+4)(x^2-5x+6)-120令x^2-5x=A原式=(A+4)(A+6)-120=A^2+10A-96=(A-6)(A+16)=(x^2-5x-6)(x^2-5x+16)5)4x^2-4x-y^2+4y-3 =4x^2-4x+1-y^2+4y-4 =(2x-1)^2-(y^2-4y+4) =(2x-1)^2-(y-2)^2 =(2x-1+y-2)(2x-1-y+2) =(2x+y-3)(2x-y+1) 6)2x^2-5xy+x-3y^2+11y-6=2x^2+(1-5y)x-(y-3)(3y-2)=[x-(3y-2)][2x+(y-3)]=(x-3y+2)(2x+y-3)
1. (x+4)(x-9)2. (x-2)(x-12)3. (x+2)(x-4)4. (-a-2)(a+1)5. (x^2+x+1)(x^2+5)6. (7m+7n+5)(2m+2n-3)7. (x-7)(x-m-1)8. x^n(x-1)(x-4)9. (x-5)(x+5)(x^2+4)10. x^2(x-...
1.（X-9）*（X+4）2.（X-2）*（X-12）3.（X-4）*（X+2）4.-（a+1）*(a+2)5.6.(2m+2n-3)*(7m+7n+5)7.(X-7)*(X-m-8)8.x^n（X-4）*(X-1)9.(x^2-25）*（x^2+4）10.x^2（x-7）*（x+4）11.（x-5...
1.（X-9）*（X+4）2.（X-2）*（X-12）3.（X-4）*（X+2）
您可能关注的推广回答者：⒊道初⒉的因式分解:1.(x^2+5x+4)(x^2+5x+6)-12.(x^2-3x+4)(x^2-3x-3)-83.(x+1)(x+2)(x+3)(x+4)+12T未抄错_百度作业帮
⒊道初⒉的因式分解:1.(x^2+5x+4)(x^2+5x+6)-12.(x^2-3x+4)(x^2-3x-3)-83.(x+1)(x+2)(x+3)(x+4)+12T未抄错
一题应为+1而不是-1就对了将（x^2+5x）看成一体=（x^2+5x+5）^2二题：(x^2-3x+4)(x^2-3x-3)-8 将(x^2-3x)看成一体 =(x^2-3x)^2+(x^2-3x)-12-8 =(x^2-3x-4)(x^2-3x+5) 三题：(x+1)(x+2)(x+3)(x+4)+1=[（x+1）（x+4)][(x+2)(x+3)]+1=(x^2+5x+4)(x^2+5x+6)+1将（x^2+5x）看成一体=(x^2+5x)^2+10(x^2+5x)+24+1==（x^2+5x+5）^2
1.(X+1)(X+4)(X+2)(X+3)-1 2.(x-3x+5)(x-4)(x+1)3.(x^2+5x+4)(x^2+5x+6)+1
1.这题跟三题很象,会不会错了,我解不出2.(x^2-3x+4)(x^2-3x-3)-8 将(x^2-3x)看成一体 =(x^2-3x)^2+(x^2-3x)-12-8 =(x^2-3x-4)(x^2-3x+5)3.(x+1)(x+2)(x+3)(x+4)+1
=(x^2+5x+4)(x^2+5x+6)+1
将(x^2+5x)看成一体 =(x^2+5x)^2+10(x^2+5x)+24+1 =(x^2+5x+5)^2
1.(x^2+5x+4)(x^2+5x+6)-1 =(x^2+5x+4)(x^2+5x+4+2)-1
=(x^2+5x+4)^2+2(x^2+5x+4)-1
=(x^2+5x+4+1)^2-2
=(x^2+5x+5+√2)(x^2+5x+5-√2)2.(x^2-3x+4)(x^2-3x-3)-8 =(x^2-3x-3+7)(x^2-3x-3)-8...
1.(X+1)(X+4)(X+2)(X+3)-12.你是非抄错3。（(x^2+5x+4)(x^2+5x+6)+1
第1个无法分解第2个(x-4) (x+1) (x2-3x+5) 第3个(x2+5x+5)^2
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