1. 5/23×10/9+5/27÷9/10 2.（9/8-3/1）÷（18/7×3/2） 3. （7/1-9/1）×63-3/2是脱式计算下面还有一题4. 15/8×〔4/3+（16/7-4/1）]_作业帮
拍照搜题，秒出答案
1. 5/23×10/9+5/27÷9/10 2.（9/8-3/1）÷（18/7×3/2） 3. （7/1-9/1）×63-3/2是脱式计算下面还有一题4. 15/8×〔4/3+（16/7-4/1）]
1. 5/23×10/9+5/27÷9/10 2.（9/8-3/1）÷（18/7×3/2） 3. （7/1-9/1）×63-3/2是脱式计算下面还有一题4. 15/8×〔4/3+（16/7-4/1）]
这个要慢慢练的，不能什么都让人代为做了。关于初中的算术（-3）+（-7）=（-23）+0=（-17）+21=（-13）+5 =45+（-45）=45+（-23）=（-3）-（-7）=33-（-27）=（-4）-16 =（-10）-3 =0-12=-6-（-6）=（-4）*5=（-8）*1.25=（-7/10）*（-3/14）=（-5）*（-7）=4/5*_作业帮
拍照搜题，秒出答案
关于初中的算术（-3）+（-7）=（-23）+0=（-17）+21=（-13）+5 =45+（-45）=45+（-23）=（-3）-（-7）=33-（-27）=（-4）-16 =（-10）-3 =0-12=-6-（-6）=（-4）*5=（-8）*1.25=（-7/10）*（-3/14）=（-5）*（-7）=4/5*
关于初中的算术（-3）+（-7）=（-23）+0=（-17）+21=（-13）+5 =45+（-45）=45+（-23）=（-3）-（-7）=33-（-27）=（-4）-16 =（-10）-3 =0-12=-6-（-6）=（-4）*5=（-8）*1.25=（-7/10）*（-3/14）=（-5）*（-7）=4/5*（-25/6）=（-8）*4/11*0=
（-3）+（-7）=-10（-23）+0=-23（-17）+21=3（-13）+5 =-845+（-45）=045+（-23）=22（-3）-（-7）=433-（-27）=60（-4）-16 =-20（-10）-3 =-130-12=-12-6-（-6）=0（-4）*5=-20（-8）*1.25=10（-7/10）*（-3/14）=3/20（-5）*（-7）=354/5*（-25/6）=-10/3（-8）*4/11*0= 0好好学习!
（-3）+（-7）=
-10（-23）+0=
-23（-17）+21=
4（-13）+5 =
-845+（-45）=
045+（-23）=
22（-3）-（-7）=
-1033-（-27）=
60（-4）-16 =
（-3）+（-7）=-10（-23）+0=-23（-17）+21=3（-13）+5 =-845+（-45）=045+（-23）=22（-3）-（-7）=433-（-27）=60（-4）-16 =-20（-10）-3 =-130-12=-12-6-（-6）=0（-4）*5=-20<...
分别为;-10,-23,4,-8,0,22,4,60,-20,-13,-12,0,-20,-10,0.15,35,3.3333,0
两个负数相加-a+(-b)=-(a+b)把负号提出来在相加 负数加上正数等于两个正数相减 而且负负得正~~（-3）+（-7）=-10（-23）+0=-23（-17）+21=3（-13）+5 =-845+（-45）=045+（-23）=22（-3）-（-7）=433-（-27）=60（-4）-16 =-20<b...
（-3）+（-7）=-10（-23）+0=-23（-17）+21=3（-13）+5 =-845+（-45）=045+（-23）=22（-3）-（-7）=433-（-27）=60（-4）-16 =-20（-10）-3 =-130-12=-12-6-（-6）=0（-4）*5=-20<...Other Product
2,4-Pyrrolidinedione,1-methyl-3-[(2E,4S,6R,8R,9R,10S,11R,13S,14S,15R,16S,17R,19R,21S,23S,25S,26S,27R,28R,29S)-1,8,9,11,13,15,17,19,21,23,25,26,27,28,29-pentadecahydroxy-2,4,6,10,14,16-hexamethyl-30-[(2R,3S,4S,5S,6S)-tetrahydro-3,4,5,6-tetrahydroxy-6-[(2R)-2-hydroxydodecyl]-2H-pyran-2-yl]-2-triaconten-1-ylidene]-,(3Z)-
1/C33H42O7/c1-19-25-17-24-18-27(39-22(4)35)20(2)29(32(24,5)6)30(37)31(33(25,7)16-15-26(19)38-21(3)34)40-28(36)14-13-23-11-9-8-10-12-23/h8-14,24-27,30-31,37H,1,15-18H2,2-7H3/b14-13+/t24-,25-,26+,27+,30-,31+,33-/m1/s
1/C27H27N3O3S/c1-30-25(20-11-15-23(33-3)16-12-20)24(19-9-13-22(32-2)14-10-19)29-27(30)34-18-17-28-26(31)21-7-5-4-6-8-21/h4-16H,17-18H2,1-3H3,(H,28,31
1/C51H74N2/c1-5-9-13-17-21-49(22-18-14-10-6-2)42-53(43-50(23-19-15-11-7-3)24-20-16-12-8-4)51-39-37-47(38-40-51)32-31-45-27-25-44(26-28-45)29-30-46-33-35-48(41-52)36-34-46/h25-40,49-50H,5-24,42-43H2,1-4H3/b30-29+,32-31
1/C28H41N5O15S.Na/c1-12(2)21(28(42)43)33-26(41)17(9-15-5-7-16(8-6-15)48-49(44,45)46)31-25(40)18(29-13(3)35)10-20(37)32-27-22(30-14(4)36)24(39)23(38)19(11-34)47-27;/h5-8,12,17-19,21-24,27,34,38-39H,9-11H2,1-4H3,(H,29,35)(H,30,36)(H,31,40)(H,32,37)(H,33,41
1/C26H18O2/c1-17-16-23-21-9-5-3-7-19(21)11-13-25(23)28-26(17)15-14-22-20-8-4-2-6-18(20)10-12-24(22)27-26/h2-16H,1H
1/C22H28O6/c1-23-17-11-21(27-5)19(25-3)9-15(17)13-7-8-14(13)16-10-20(26-4)22(28-6)12-18(16)24-2/h9-14H,7-8H2,1-6H3/t13-,14
4,10,14,29,30-Pentaoxa-32-azapentacyclo[23.3.1.12,5.19,13.119,23]dotriaconta-2,5(32),6,16-tetraen-15-one,11-[(1E)-2-[2-[[(2S,4R,6R)-6-[(1R,2E,4E,6R,8E)-9-bromo-1-hydroxy-6-methoxy-3-methyl-2,4,8-nonatrienyl]tetrahydro-2-hydroxy-4-methoxy-2H-pyran-2-yl]methyl]-4-oxazolyl]-1-methylethenyl]-27-hydroxy-12,31-dimethyl-21-methylene-,(1R,6E,9R,11R,12R,13S,16Z,19S,23R,25S,27S,31S)-
1/C21H26N2O4/c1-3-14-8-9-19(25)23(12-14)11-10-16-15-6-4-5-7-18(15)22-20(16)17(13-24)21(26)27-2/h4-7,12,17,22,24H,3,8-11,13H2,1-2H
1/C19H15ClN2O2S/c1-11-19(23)24-17-18(25-11)22(2)15-9-8-13(20)10-14(15)16(21-17)12-6-4-3-5-7-12/h3-11H,1-2H
2,4-Pyrrolidinedione,3-[(2E,4S,6R,8R,9R,10S,11R,12R,13R,14S,15R,17S,18S,19R,20S,21R,23R,25S,27S,28S,29R,30R,31S)-1,8,9,11,13,15,17,19,21,23,25,27,28,29,30,31-hexadecahydroxy-2,4,6,10,12,14,18,20-octamethyl-32-[(2R,3S,4S,5S,6S)-tetrahydro-3,4,5,6-tetrahydroxy-6-[(2R)-2-hydroxyundecyl]-2H-pyran-2-yl]-2-dotriaconten-1-ylidene]-1,5-dimethyl-,(3Z,5R)- (Molecular Formula: C62H115 N O24)
Product Name:
2,4-Pyrrolidinedione,3-[(2E,4S,6R,8R,9R,10S,11R,12R,13R,14S,15R,17S,18S,19R,20S,21R,23R,25S,27S,28S,29R,30R,31S)-1,8,9,11,13,15,17,19,21,23,25,27,28,29,30,31-hexadecahydroxy-2,4,6,10,12,14,18,20-octamethyl-32-[(2R,3S,4S,5S,6S)-tetrahydro-3,4,5,6-tetrahydroxy-6-[(2R)-2-hydroxyundecyl]-2H-pyran-2-yl]-2-dotriaconten-1-ylidene]-1,5-dimethyl-,(3Z,5R)-
CAS Registry Number:
2,4-Pyrrolidinedione,3-[(2E,4S,6R,8R,9R,10S,11R,12R,13R,14S,15R,17S,18S,19R,20S,21R,23R,25S,27S,28S,29R,30R,31S)-1,8,9,11,13,15,17,19,21,23,25,27,28,29,30,31-hexadecahydroxy-2,4,6,10,12,14,18,20-octamethyl-32-[(2R,3S,4S,5S,6S)-tetrahydro-3,4,5,6-tetrahydroxy-6-[(2R)-2-hydroxyundecyl]-2H-pyran-2-yl]-2-dotriacontenylidene]-1,5-dimethyl-,(3Z,5R)- (9CI); Aflastatin A; N-Methylaflastatin B
Molecular Structure:
Molecular Formula:
C62H115 N O24
&1.298g/cm3
Boiling Point:
&6;Cat760mmHg
Flash Point:
&764&#176;C
Refractive index:√为根号化简√8a&sup2;b&sup3; √72a&sup2;b&sup3; c √5&sup2;+12&sup2;（在一个根号里的）√72 √32x&sup3;y&sup2;z计算 √44×（-√33）3√6×2√27√18×√20×√75√3&sup2;×4&sup3;×5（√5-√3）（√5+√3）一共10_作业帮
拍照搜题，秒出答案
√为根号化简√8a&sup2;b&sup3; √72a&sup2;b&sup3; c √5&sup2;+12&sup2;（在一个根号里的）√72 √32x&sup3;y&sup2;z计算 √44×（-√33）3√6×2√27√18×√20×√75√3&sup2;×4&sup3;×5（√5-√3）（√5+√3）一共10
√为根号化简√8a&sup2;b&sup3; √72a&sup2;b&sup3; c √5&sup2;+12&sup2;（在一个根号里的）√72 √32x&sup3;y&sup2;z计算 √44×（-√33）3√6×2√27√18×√20×√75√3&sup2;×4&sup3;×5（√5-√3）（√5+√3）一共10道题 答得好还加分
楼上有不同程度粗心而至的差错,正确如下：√8a&sup2;b&sup3;=√2×2&sup2;a&sup2;b&sup2;b=2ab√2b √72a&sup2;b&sup3;c=√2×6&sup2;a&sup2;b&sup2;bc=6ab√2bc √5&sup2;+12&sup2;=√169=√13&sup2;=13√72=√2×6&sup2;=6√2 √32x&sup3;y&sup2;z=√2×4&sup2;x&sup2;xy&sup2;z=4xy√2xz√44×（-√33）＝－√2&sup2;×11×(3×11)＝－√(2×11)&sup2;×3＝－22√33√6×2√27＝3×2√(2×3)×3&sup3;＝6√2×9&sup2;＝6×9√2＝54√2√18×√20×√75＝√(2×3&sup2;)×(2&sup2;×5)×(3×5&sup2;)＝3×2×5√2×5×3＝30√30√3&sup2;×4&sup3;×5＝√3&sup2;×4&sup2;×2&sup2;×5＝3×4×2√5＝24√5（√5-√3）（√5+√3）＝√5&sup2;＋√5×3－√3×5－√3&sup2;＝5－3＝2
化简2ab√2b,6ab√2bc,13,6√2,4xy√2xz
2ab√2b,6ab√2b -22√3
2,13,6√2,4xy√2xz
化简计算哪来的过程...2ab√2
4xy√xz-22√3
2（平方差公式）&#179;√(-5)&#179;×(-1/5)&#178;-√(-3)&#178;+&#179;√-8/27÷(1/3)&#178; 求解答过程?&#179;√(-5)&#179;×(-1/5)&#178;-√(-3)&#178;+&#179;√-8/27÷(1/3)&#178;
求解答过程?_作业帮
拍照搜题，秒出答案
&#179;√(-5)&#179;×(-1/5)&#178;-√(-3)&#178;+&#179;√-8/27÷(1/3)&#178; 求解答过程?&#179;√(-5)&#179;×(-1/5)&#178;-√(-3)&#178;+&#179;√-8/27÷(1/3)&#178;
求解答过程?
&#179;√(-5)&#179;×(-1/5)&#178;-√(-3)&#178;+&#179;√-8/27÷(1/3)&#178; 求解答过程?&#179;√(-5)&#179;×(-1/5)&#178;-√(-3)&#178;+&#179;√-8/27÷(1/3)&#178;
求解答过程?
任何一个数的奇数次幂开奇数次根结果就是它本身，而如果是偶数次幂开偶数次根则取绝对值，提示的够明显了
=-5×1/25－3+（-2/3）÷1/9＝-1/5－3－6＝-1/5－9＝-46/5