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已知二次函数图像的顶点是负一二节过点零二分之三求证二次函数的表达式
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已知二次函数图像的顶点是(-1,2)且过点（0,3/2）求证二次函数的表达式y=ax^2+bx+c=a(x+b/2a)^2-(b^2-4ac)/4a-b/2a=-1, b=2a,
-(b^2-4ac)/4a=2 ,
, -2a^2-a=0, a=0或-1/2 , b=0或-1二次函数的表达式y=-(1/2)x^2-x+3/2
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扫描下载二维码Protein Symmetry: Asymmetric ()
Protein Stoichiometry: Monomer
Protein Symmetry: C1 ()
Protein Stoichiometry: A
Protein Symmetry: C1 ()
Protein Stoichiometry: A
Protein Symmetry: C1 ()
Protein Stoichiometry: A
Protein Symmetry: C2 ()
Protein Stoichiometry: A2
Protein Symmetry: C2 ()
Protein Stoichiometry: A2
Macromolecule Content
Unique protein chains: 1
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CK1d in complex with 9-[3-(4-fluorophenyl)-1-methyl-1H-pyrazol-4-yl]-2,3,4,5-tetrahydropyrido[2,3-f][1,4]oxazepine inhibitor
DOI: 10.2210/pdb4kba/pdb
Classification:
Deposited:
Deposition author(s):
Expression System:
Spodoptera frugiperda
Experimental Data Snapshot
X-RAY DIFFRACTION
Resolution: 1.98
R-Value Free: 0.237
R-Value Work: 0.208
wwPDB Validation
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Total Structure Weight:
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Casein kinase I isoform delta
A, B, C, D
Metabolic Pathways
Maps:&&&&&&&
Reactions:
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Protein Feature View - UniProtKB AC:
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Ligands 2 Unique
Name / Formula / InChI Key
2D Diagram & Interactions
3D Interactions
A, B, C, D
9-[3-(4-fluorophenyl)-1-methyl-1H-pyrazol- 4-yl]-2,3,4,5-tetrahydropyrido[2,3-f][1,4]oxazepine
C18 H17 F N4 O
RDUXJEGWTNOYDA-UHFFFAOYSA-N
Black dashed lines indicate hydrogen bonds, salt bridges, and metal interactions. Green solid line show hydrophobic interactions and green dashed lines show π-π and π-cation interactions.
Source Information
Interactions are determined by geometric criteria as described in K. Stierand, M. Rarey (2010),
Drawing the PDB: Protein-ligand complexes in two dimensions, ACS Med. Chem. Lett., DOI:
Ions and some metal complexes are excluded, as well as cases where no
interaction profile could be generated. Poseview diagrams can be calculated
for approximately 92% of the remaining complexes in the PDB.
is developed at the
Center for Bioinformatics Hamburg
and jointly provided with
as a community service at the PDB.
is provided by BioSolveIT.
A, B, C, D
SULFATE ION
QAOWNCQODCNURD-UHFFFAOYSA-L
Black dashed lines indicate hydrogen bonds, salt bridges, and metal interactions. Green solid line show hydrophobic interactions and green dashed lines show π-π and π-cation interactions.
Source Information
Interactions are determined by geometric criteria as described in K. Stierand, M. Rarey (2010),
Drawing the PDB: Protein-ligand complexes in two dimensions, ACS Med. Chem. Lett., DOI:
Ions and some metal complexes are excluded, as well as cases where no
interaction profile could be generated. Poseview diagrams can be calculated
for approximately 92% of the remaining complexes in the PDB.
is developed at the
Center for Bioinformatics Hamburg
and jointly provided with
as a community service at the PDB.
is provided by BioSolveIT.
External Ligand Annotations
Binding Affinity (Sequence Identity %)
Experimental Data
X-RAY DIFFRACTION
Resolution: 1.98 &A
R-Value Free: 0.237
R-Value Work: 0.208
Space Group:
Unit Cell:
Length (&A)
& = 108.00
& = 105.71
Structure Validation
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Deposited Date:
Released Date:
Deposition author(s):
Revision History
Version 1_0: Type: Initial release
Version 1_1: Type: Database references
RCSB PDB () is managed by two members of the Research Collaboratory for Structural Bioinformatics: Rutgers and UCSD/SDSC
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1次函数y等于2x减6,y等于负1/2x-1与y等于三分之二x+三分之m的图像交于一点,求m的值
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y=2x-6,y=-½x-1联立得到2x-6=-1/2x-1
x=2所以交点是（2,-2）所以y=2/3x+m/3经过（2,-2）得到4/3+m/3=-2m=-10 答题不易、满意请给个好评、你的认可是我最大的动力、祝你学习愉快、>_
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已知函数f(x)=k*a的负x次方的图象过点(0,1),B（3,8）(k,a为常数,a＞0且a≠1）1求实数k,a的值2若函数g（x）=f（x）+1分之f（x)-1,试判断函数g（x）的奇偶性并说明理由
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1∵函数f(x)=k*a^(-x)图象过点(0,1),B（3,8）∴f(0)=k=1,f(3)=a^(-3)=8==>a=1/2∴k=1,a=1/22. f(x)=(1/2)^(-x)=2^xg(x)=f(x)+1/f(x)-1=2^x+1/2^x-1g(-x)=2^(-x)+1/2^(-x)-1
=1/2^x+2^x-1 =g(x) ∴g(-x)=g(x)∴函数g（x）是偶函数
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好的，正解
扫描下载二维码已知对数函数的图像过点(三分之一,负一)求表达式f(x)和f(81)_百度知道
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已知对数函数的图像过点(三分之一,负一)求表达式f(x)和f(81)
f(x)=loga(x)f(1/3)=-1loga(1/3)=-1a^-1=1/3a=3所以f(x)=log3(x)f(81)=log3(3^4)=4
采纳率：75%
来自团队：
解：设f(x)=logax
注这里a是底数由题意对数函数的图像过点(1/3，-1)得f(1/3)=loga(-1) 所以a^(-1)=1/3
则a=3所以f(x)=log3x
（3为底x的对数) f(81)=log3 81=log3 3^4=4
借古讽今华国锋就会
log(a)x=f(x),f(1/3)=-1,f(1/3)=log(a)(1/3)=-log(a)3=-1,∴a=3,f(x)=log(3)xf(81)=4
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